(-1/5)^3+2q^2+3.75q-200=0

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Solution for (-1/5)^3+2q^2+3.75q-200=0 equation: 


q in (-oo:+oo)

2*q^2+3.75*q+(-1/5)^3-200 = 0

2*q^2+3.75*q-25001/125 = 0

DELTA = 3.75^2-(-25001/125*2*4)

DELTA = 3.75^2+200008/125

DELTA = 1614.1265

DELTA > 0

q = ((3.75^2+200008/125)^(1/2)-3.75)/(2*2) or q = (-(3.75^2+200008/125)^(1/2)-3.75)/(2*2)

q = ((3.75^2+200008/125)^(1/2)-3.75)/4 or q = (-((3.75^2+200008/125)^(1/2)+3.75))/4

q in { (-((3.75^2+200008/125)^(1/2)+3.75))/4, ((3.75^2+200008/125)^(1/2)-3.75)/4 }

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